(x^2-1)(x^2-4x+4)=0

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Solution for (x^2-1)(x^2-4x+4)=0 equation: 


Simplifying
(x2 + -1)(x2 + -4x + 4) = 0

Reorder the terms:
(-1 + x2)(x2 + -4x + 4) = 0

Reorder the terms:
(-1 + x2)(4 + -4x + x2) = 0

Multiply (-1 + x2) * (4 + -4x + x2)
(-1(4 + -4x + x2) + x2(4 + -4x + x2)) = 0
((4 * -1 + -4x * -1 + x2 * -1) + x2(4 + -4x + x2)) = 0
((-4 + 4x + -1x2) + x2(4 + -4x + x2)) = 0
(-4 + 4x + -1x2 + (4 * x2 + -4x * x2 + x2 * x2)) = 0
(-4 + 4x + -1x2 + (4x2 + -4x3 + x4)) = 0

Combine like terms: -1x2 + 4x2 = 3x2
(-4 + 4x + 3x2 + -4x3 + x4) = 0

Solving
-4 + 4x + 3x2 + -4x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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